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一次函数求最值，设0<k<1,y=kx+1/k(1-x),当1≤x≤2时，求y最大值
设0
一次函数合集44/59
App03:29
App08:30
App06:34
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App07:25
App08:06
App08:33
App05:08
App08:09
App03:33
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App04:37
App03:42打开App观看
设0
App03:29App08:30App06:34App06:34App07:25App08:06App08:33App05:08App08:09App03:33App04:26App04:37App03:42
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