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【高等数学习题】如何间接法求函数的高阶导数?|莱布尼茨公式
[高等数学学习系列] 在这个视频中, 我们利用莱布尼茨公式求函数 y = x^2*sin(2x) 的 50 阶导数. 还利用了幂函数的任意阶导数公式, 和正弦函数的任意阶导数公式.
高等数学(上)习题集55/264
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App04:40![求积分技巧: 通过配方法,转化为基本积分表中的积分形式[084]](http://p26-sign.bdxiguaimg.com/tos-cn-i-0004/6d55da2b3be24bd19f56eaf69df5b898~tplv-pk90l89vgd-crop-center:576:324.jpeg?appId=3586&channelId=0&customType=custom%2Fnone&from=704_middle_image&imageType=list&isImmersiveScene=0&is_ios=1&is_stream=0&lk3s=9d3f5bff&logId=202411060526597B99473878B6D74A94B7&requestFrom=704&version_code=80402&x-expires=1762378019&x-signature=LDjZ8gzgUoyYDsYYxFerlVURRDw%3D)
App10:05![求积分技巧之裂项求积,通过裂项转化为若干个积分公式的积分[085]](http://p3-sign.bdxiguaimg.com/tos-cn-i-0004/1388b6ea9efc470bbd77cf0b2bd20309~tplv-pk90l89vgd-crop-center:576:324.jpeg?appId=3586&channelId=0&customType=custom%2Fnone&from=704_middle_image&imageType=list&isImmersiveScene=0&is_ios=1&is_stream=0&lk3s=9d3f5bff&logId=202411060526597B99473878B6D74A94B7&requestFrom=704&version_code=80402&x-expires=1762378019&x-signature=gosdFJ2Ivyz3V%2Fab3jr66eEfNHk%3D)
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App08:43![求积分技巧之凑微分法(2), 最基础也是最重要的求积分方法[087]](http://p26-sign.bdxiguaimg.com/tos-cn-i-0004/9de6447729cb4290a20668a0693a96a6~tplv-pk90l89vgd-crop-center:576:324.jpeg?appId=3586&channelId=0&customType=custom%2Fnone&from=704_middle_image&imageType=list&isImmersiveScene=0&is_ios=1&is_stream=0&lk3s=9d3f5bff&logId=202411060526597B99473878B6D74A94B7&requestFrom=704&version_code=80402&x-expires=1762378019&x-signature=O%2BXuXpgHHRwsaJ6arTBXjkM4Ll0%3D)
App07:58![求积分技巧之分部积分法; 三指幂对反, 顺序不能忘[088]](http://p26-sign.bdxiguaimg.com/tos-cn-i-0004/b2cd6ade410a4c14b8075e354d01110c~tplv-pk90l89vgd-crop-center:576:324.jpeg?appId=3586&channelId=0&customType=custom%2Fnone&from=704_middle_image&imageType=list&isImmersiveScene=0&is_ios=1&is_stream=0&lk3s=9d3f5bff&logId=202411060526597B99473878B6D74A94B7&requestFrom=704&version_code=80402&x-expires=1762378019&x-signature=%2B6ochFHRxQkr0QaTgWhzr9vaYmU%3D)
App08:18![三角代换使用说明, sec^2t = 1 + tan^2t [090]](http://p3-sign.bdxiguaimg.com/tos-cn-i-0004/799c75786a0044b5958adf7d2ba7ff48~tplv-pk90l89vgd-crop-center:576:324.jpeg?appId=3586&channelId=0&customType=custom%2Fnone&from=704_middle_image&imageType=list&isImmersiveScene=0&is_ios=1&is_stream=0&lk3s=9d3f5bff&logId=202411060526597B99473878B6D74A94B7&requestFrom=704&version_code=80402&x-expires=1762378019&x-signature=zt4D%2FK29mugvJQhrWnp4Okh5zoo%3D)
App09:27![三角代换使用说明, cos^2t = 1 - sin^2t [091]](http://p26-sign.bdxiguaimg.com/tos-cn-i-0004/fc4b46ea8d6741a594ac5c46373d5fc3~tplv-pk90l89vgd-crop-center:576:324.jpeg?appId=3586&channelId=0&customType=custom%2Fnone&from=704_middle_image&imageType=list&isImmersiveScene=0&is_ios=1&is_stream=0&lk3s=9d3f5bff&logId=202411060526597B99473878B6D74A94B7&requestFrom=704&version_code=80402&x-expires=1762378019&x-signature=1AYOzVs9%2BRfHeaCWI0tLDNF6nFM%3D)
App11:49![根号? 根号! 换掉它! 根式代换 [092]](http://p3-sign.bdxiguaimg.com/tos-cn-i-0004/911fb0cbd92441f5a7134c6854171552~tplv-pk90l89vgd-crop-center:576:324.jpeg?appId=3586&channelId=0&customType=custom%2Fnone&from=704_middle_image&imageType=list&isImmersiveScene=0&is_ios=1&is_stream=0&lk3s=9d3f5bff&logId=202411060526597B99473878B6D74A94B7&requestFrom=704&version_code=80402&x-expires=1762378019&x-signature=6b%2BubjSC%2BP8n9KcAk0mlYIkHxx0%3D)
App09:58![根式代换就是替换掉不易求解的根号部分 [093]](http://p26-sign.bdxiguaimg.com/tos-cn-i-0004/2f5944aa6d734c3d96a519c34f127c88~tplv-pk90l89vgd-crop-center:576:324.jpeg?appId=3586&channelId=0&customType=custom%2Fnone&from=704_middle_image&imageType=list&isImmersiveScene=0&is_ios=1&is_stream=0&lk3s=9d3f5bff&logId=202411060526597B99473878B6D74A94B7&requestFrom=704&version_code=80402&x-expires=1762378019&x-signature=YBt2jznnvW47yxL9dFu9rFbnB0Q%3D)
App09:06![两道解题思路不拐弯的积分题|第二类换元法|裂项求积 [094]](http://p26-sign.bdxiguaimg.com/tos-cn-i-0004/51fe2817a9f14283b33219e7901dc016~tplv-pk90l89vgd-crop-center:576:324.jpeg?appId=3586&channelId=0&customType=custom%2Fnone&from=704_middle_image&imageType=list&isImmersiveScene=0&is_ios=1&is_stream=0&lk3s=9d3f5bff&logId=202411060526597B99473878B6D74A94B7&requestFrom=704&version_code=80402&x-expires=1762378019&x-signature=A10HlHImH1y8qWCTAi3votbEIFw%3D)
App08:35![根式代换与三角代换都可以求解的两道题 [095]](http://p3-sign.bdxiguaimg.com/tos-cn-i-0004/f040bca229ed4f94a33f87c1f89d2ceb~tplv-pk90l89vgd-crop-center:576:324.jpeg?appId=3586&channelId=0&customType=custom%2Fnone&from=704_middle_image&imageType=list&isImmersiveScene=0&is_ios=1&is_stream=0&lk3s=9d3f5bff&logId=202411060526597B99473878B6D74A94B7&requestFrom=704&version_code=80402&x-expires=1762378019&x-signature=SYpkXncm4lywRguRkFQvs3AYSTo%3D)
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